7/(3x^2+8)=8

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Solution for 7/(3x^2+8)=8 equation: 


D( x )

3*x^2+8 = 0

3*x^2+8 = 0

3*x^2+8 = 0

3*x^2 = -8 // : 3

x^2 = -8/3

x in (-oo:+oo)

7/(3*x^2+8) = 8 // - 8

7/(3*x^2+8)-8 = 0

7/(3*x^2+8)+(-8*(3*x^2+8))/(3*x^2+8) = 0

7-8*(3*x^2+8) = 0

-24*x^2-57 = 0

(-24*x^2-57)/(3*x^2+8) = 0

(-24*x^2-57)/(3*x^2+8) = 0 // * 3*x^2+8

-24*x^2-57 = 0

-24*x^2 = 57 // : -24

x^2 = -19/8

x belongs to the empty set

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